consistent-generic-constructors
Enforce specifying generic type arguments on type annotation or constructor name of a constructor call.
Extending "plugin:@typescript-eslint/stylistic"
in an ESLint configuration enables this rule.
Some problems reported by this rule are automatically fixable by the --fix
ESLint command line option.
When constructing a generic class, you can specify the type arguments on either the left-hand side (as a type annotation) or the right-hand side (as part of the constructor call):
// Left-hand side
const map: Map<string, number> = new Map();
// Right-hand side
const map = new Map<string, number>();
This rule ensures that type arguments appear consistently on one side of the declaration. Keeping to one side consistently improve code readability.
The rule never reports when there are type parameters on both sides, or neither sides of the declaration. It also doesn't report if the names of the type annotation and the constructor don't match.
- Flat Config
- Legacy Config
export default tseslint.config({
rules: {
"@typescript-eslint/consistent-generic-constructors": "error"
}
});
module.exports = {
"rules": {
"@typescript-eslint/consistent-generic-constructors": "error"
}
};
Try this rule in the playground ↗
Options
This rule accepts the following options:
type Options = [
/** Which constructor call syntax to prefer. */
| 'constructor'
/** Which constructor call syntax to prefer. */
| 'type-annotation',
];
const defaultOptions: Options = ['constructor'];
'constructor'
(default): type arguments that only appear on the type annotation are disallowed.'type-annotation'
: type arguments that only appear on the constructor are disallowed.
'constructor'
- ❌ Incorrect
- ✅ Correct
const map: Map<string, number> = new Map();
const set: Set<string> = new Set();
Open in Playgroundconst map = new Map<string, number>();
const map: Map<string, number> = new MyMap();
const set = new Set<string>();
const set = new Set();
const set: Set<string> = new Set<string>();
Open in Playground'type-annotation'
- ❌ Incorrect
- ✅ Correct
const map = new Map<string, number>();
const set = new Set<string>();
Open in Playgroundconst map: Map<string, number> = new Map();
const set: Set<string> = new Set();
const set = new Set();
const set: Set<string> = new Set<string>();
Open in PlaygroundWhen Not To Use It
You can turn this rule off if you don't want to enforce one kind of generic constructor style over the other.
However, keep in mind that inconsistent style can harm readability in a project. We recommend picking a single option for this rule that works best for your project.