consistent-type-assertions
Enforce consistent usage of type assertions.
Extending "plugin:@typescript-eslint/stylistic"
in an ESLint configuration enables this rule.
Some problems reported by this rule are automatically fixable by the --fix
ESLint command line option.
Some problems reported by this rule are manually fixable by editor suggestions.
TypeScript provides two syntaxes for "type assertions":
- Angle brackets:
<Type>value
- As:
value as Type
This rule aims to standardize the use of type assertion style across the codebase. Keeping to one syntax consistently helps with code readability.
Type assertions are also commonly referred as "type casting" in TypeScript. However, that term is technically slightly different to what is understood by type casting in other languages. Type assertions are a way to say to the TypeScript compiler, "I know better than you, it's actually this different type!".
const
assertions are always allowed by this rule.
Examples of them include let x = "hello" as const;
and let x = <const>"hello";
.
- Flat Config
- Legacy Config
export default tseslint.config({
rules: {
"@typescript-eslint/consistent-type-assertions": "error"
}
});
module.exports = {
"rules": {
"@typescript-eslint/consistent-type-assertions": "error"
}
};
Try this rule in the playground ↗
Options
This rule accepts the following options:
type Options = [
| {
/** The expected assertion style to enforce. */
assertionStyle:
| 'angle-bracket'
/** The expected assertion style to enforce. */
| 'as';
/** Whether to always prefer type declarations for object literals used as variable initializers, rather than type assertions. */
objectLiteralTypeAssertions?:
| 'allow-as-parameter'
| 'never'
/** Whether to always prefer type declarations for object literals used as variable initializers, rather than type assertions. */
| 'allow';
}
| {
/** The expected assertion style to enforce. */
assertionStyle: /** The expected assertion style to enforce. */
'never';
},
];
const defaultOptions: Options = [
{ assertionStyle: 'as', objectLiteralTypeAssertions: 'allow' },
];
assertionStyle
The expected assertion style to enforce. Default: "as"
.
Valid values for assertionStyle
are:
as
will enforce that you always use... as foo
.angle-bracket
will enforce that you always use<foo>...
never
will enforce that you do not do any type assertions.
Most codebases will want to enforce not using angle-bracket
style because it conflicts with JSX syntax, and is confusing when paired with generic syntax.
Some codebases like to go for an extra level of type safety, and ban assertions altogether via the never
option.
objectLiteralTypeAssertions
Whether to always prefer type declarations for object literals used as variable initializers, rather than type assertions. Default: "allow"
.
For example, this would prefer const x: T = { ... };
to const x = { ... } as T;
(or similar with angle brackets).
The type assertion in the latter case is either unnecessary or will probably hide an error.
The compiler will warn for excess properties with this syntax, but not missing required fields. For example: const x: { foo: number } = {};
will fail to compile, but const x = {} as { foo: number }
will succeed.
The const assertion const x = { foo: 1 } as const
, introduced in TypeScript 3.4, is considered beneficial and is ignored by this option.
Assertions to any
are also ignored by this option.
Examples of code for { assertionStyle: 'as', objectLiteralTypeAssertions: 'never' }
:
- ❌ Incorrect
- ✅ Correct
const x = { foo: 1 } as T;
function bar() {
return { foo: 1 } as T;
}
Open in Playgroundconst x: T = { foo: 1 };
const y = { foo: 1 } as any;
const z = { foo: 1 } as unknown;
function bar(): T {
return { foo: 1 };
}
Open in PlaygroundExamples of code for { assertionStyle: 'as', objectLiteralTypeAssertions: 'allow-as-parameter' }
:
- ❌ Incorrect
- ✅ Correct
const x = { foo: 1 } as T;
function bar() {
return { foo: 1 } as T;
}
Open in Playgroundconst x: T = { foo: 1 };
const y = { foo: 1 } as any;
const z = { foo: 1 } as unknown;
bar({ foo: 1 } as T);
new Clazz({ foo: 1 } as T);
function bar() {
throw { foo: 1 } as Foo;
}
const foo = <Foo props={{ bar: 1 } as Bar} />;
Open in PlaygroundWhen Not To Use It
If you do not want to enforce consistent type assertions.
However, keep in mind that inconsistent style can harm readability in a project. We recommend picking a single option for this rule that works best for your project.